5a^2-11a+10=4

Solution for 5a^2-11a+10=4 equation:

5a^2-11a+10=4

We move all terms to the left:

5a^2-11a+10-(4)=0

We add all the numbers together, and all the variables

5a^2-11a+6=0

a = 5; b = -11; c = +6;
Δ = b2-4ac
Δ = -112-4·5·6
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-1}{2*5}=\frac{10}{10}
=1
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+1}{2*5}=\frac{12}{10}
=1+1/5
$